Import Question JSON

Current Question (ID: 18427)

Question:

$\text{The method of formation of the solution is given in Column I. Match it with the type of solution given in Column II.}$ $\text{Column I}$ $\text{(A) Sulphur vapours passed through cold water}$ $\text{(B) Soap mixed with water above critical micelle concentration}$ $\text{(C) White of egg whipped with water}$ $\text{(D) Soap mixed with water below critical micelle concentration}$ $\text{Column II}$ $1. \text{Normal electrolyte solution}$ $2. \text{Molecular colloids}$ $3. \text{Associated colloid}$ $4. \text{Macromolecular colloids}$ $\text{Codes}$

Options:

1. $1. \ 2 \ 3 \ 4$
2. $1. \ 2 \ 4 \ 3$
3. $1. \ 4 \ 3 \ 2$
4. $4 \ 1 \ 3 \ 2$

Solution:

$\text{Hint: Colloids are mixtures in which microscopically dispersed insoluble particles of one substance are suspended in another substance.}$ $\text{When sulphur vapours passed through cold water it leads to the formation of molecular colloids.}$ $\text{When soap is mixed with water above critical micelle concentration it leads to the formation of associated colloids.}$ $\text{White egg whipped with water is an example of macromolecular colloids in which high molecular mass proteinaceous molecule acts as a colloidal particle.}$ $\text{Soap mixed with water below critical micelle concentration is known as the normal electrolyte solution.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}