Import Question JSON

Current Question (ID: 18432)

Question:

$\text{Select the correct option based on statements below:}$ $\text{Assertion (A): Detergents with low CMC are more economical to use.}$ $\text{Reason (R): The cleansing action of detergents involves the formation of micelles. These are formed when the concentration of detergents becomes equal to CMC.}$

Options:

1. $\text{Both (A) and (R) are true and (R) is the correct explanation of (A).}$
2. $\text{Both (A) and (R) are true but (R) is not the correct explanation of (A).}$
3. $\text{(A) is true but (R) is false.}$
4. $\text{(A) is false but (R) is true.}$

Solution:

$\text{Hint: Micelle formation takes place when the concentration of detergent becomes equal to CMC.}$ $\text{Detergents with low CMC are more economical to use as they involve the formation of micelle which is used for cleaning oil and dirt from our cloth.}$ $\text{Micelle formation takes place when the concentration of detergent becomes equal to CMC.}$ $\text{CMC is a critical indicator of micellar stability and micellization ability: the lower the CMC value, the easier it is to prepare micelles and the more stable they will be.}$ $\text{Hence, both assertion and reason are true and the reason is the correct explanation of assertion.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}