Import Question JSON

Current Question (ID: 18440)

Question:

$\text{Incorrect statement regarding colloids is:}$

Options:

1. $\text{When the size of the solute particle lies between 1 nm and 1000 nm, it behaves as a colloid.}$
2. $\text{A colloid is not a substance but a state of the substance that is dependent on the charge of the particle.}$
3. $\text{A colloidal state is an intermediate state between a true solution and a suspension.}$
4. $\text{All of the above.}$

Solution:

$\text{HINT: A colloid is a mixture in which one substance of microscopically dispersed insoluble particles are suspended throughout another substance.}$ $\text{Explanation:}$ $\text{Common salt (a typical crystalloid in an aqueous medium) behaves as a colloid in a benzene medium.}$ $\text{Hence, we can say that a colloidal substance does not represent a separate class of substances. When the size of the solute particle lies between 1 nm and 1000 nm, it behaves as a colloid.}$ $\text{Hence, we can say that colloid is not a substance but a state of the substance which is dependent on the size of the particle. A colloidal state is intermediate between a true solution and a suspension.}$ $\text{NB- formation of colloidal solution does not depend on charge, where as some property of colloidal solution like electrophoresis depends on charge and some like tyndall /brownian movement does not depends.}$ $\text{use of charge is there to coagulate, but question is neither on stability/coagulation nor properties.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}