Import Question JSON

Current Question (ID: 18463)

Question:

$\text{Match the items in Column I and Column II.}$ $\text{Column I}$ \quad \text{Column II}$ $\text{A. Dialysis} \quad \text{1. Cleansing action of soap}$ $\text{B. Peptization} \quad \text{2. Coagulation}$ $\text{C. Emulsification} \quad \text{3. Colloidal sol formation}$ $\text{D. Electrophoresis} \quad \text{4. Purification}$ $\text{Codes}$

Options:

1. $\text{A. 2} \quad \text{B. 3} \quad \text{C. 4} \quad \text{D. 1}$
2. $\text{A. 1} \quad \text{B. 2} \quad \text{C. 3} \quad \text{D. 4}$
3. $\text{A. 1} \quad \text{B. 4} \quad \text{C. 3} \quad \text{D. 2}$
4. $\text{A. 4} \quad \text{B. 3} \quad \text{C. 1} \quad \text{D. 2}$

Solution:

$\text{Hint: Peptization may be defined as the process of converting a precipitate into a colloidal sol.}$ $\text{Peptization may be defined as the process of converting a precipitate into a colloidal sol by shaking it with a dispersion medium in the presence of a small amount of electrolyte. The electrolyte used for this purpose is called a peptizing agent.}$ $\text{Dialysis: It is the process of removing a dissolved substance from a colloidal solution by means of diffusion through a suitable membrane.}$ $\text{The process of making emulsions is known as emulsification. The cleansing action of soap is due to emulsification and micelle formation.}$ $\text{The movement of colloidal particles under an applied electric potential is called electrophoresis and it is helpful in causing coagulation of colloidal solution.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}