Import Question JSON

Current Question (ID: 18465)

Question:

$\text{The charge present on micelles is:}$ $1.\ \text{Negative charge.}$ $2.\ \text{Positive charge.}$ $3.\ \text{Both negative and positive charges.}$ $4.\ \text{None of the above.}$

Options:

1. $\text{Negative charge.}$
2. $\text{Positive charge.}$
3. $\text{Both negative and positive charges.}$
4. $\text{None of the above.}$

Solution:

$\text{Soaps are basically sodium and potassium salts of long chain fatty acids,}$ $\text{R} - \text{COO}^- \text{Na}^+.$ $\text{The end of the molecule to which the sodium is attached is polar in nature,}$ $\text{while the alkyl-end is nonpolar. Thus, a soap molecule contains a hydrophilic}$ $\text{(polar) and a hydrophobic (nonpolar) part.}$ $\text{When soap is added to water containing dirt, the soap molecules surround}$ $\text{the dirt particles in such a manner that their hydrophobic parts get attached}$ $\text{to the dirt molecule and the hydrophilic parts point away from the dirt}$ $\text{molecule. This is known as micelle formation.}$ $\text{Thus, we can say that the polar group dissolves in water while the non-polar}$ $\text{group dissolves in the dirt particle. Now, as these micelles are negatively}$ $\text{charged, they do not coalesce and a stable emulsion is formed.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}