Import Question JSON

Current Question (ID: 18486)

Question:
$\text{Which of the following is an incorrect match?}$ $1.\ \text{Kaolinite} - \text{Al}_2(\text{OH})_4\text{Si}_2\text{O}_5$ $2.\ \text{Cuprite} - \text{Cu}_2\text{O}$ $3.\ \text{Siderite} - \text{FeCO}_3$ $4.\ \text{Calamine} - \text{ZnSO}_4$
Options:
  • 1. $\text{Kaolinite} - \text{Al}_2(\text{OH})_4\text{Si}_2\text{O}_5$
  • 2. $\text{Cuprite} - \text{Cu}_2\text{O}$
  • 3. $\text{Siderite} - \text{FeCO}_3$
  • 4. $\text{Calamine} - \text{ZnSO}_4$
Solution:
$\text{HINT: Calamine is a ore of zinc.}$ $\text{Explanation:}$ $1.\ \text{Kaolinite is a clay mineral, with the chemical composition Al}_2\text{Si}_2\text{O}_5(\text{OH})_4.}$ $\text{It is an important industrial mineral.}$ $\text{It is a layered silicate mineral, with one tetrahedral sheet of silica linked through oxygen atoms to one octahedral sheet of alumina octahedra.}$ $2.\ \text{Cuprite is an oxide mineral composed of copper(I) oxide Cu}_2\text{O, and is a minor ore of copper.}$ $\text{Its dark crystals with red internal reflections are in the isometric system hexoctahedral class, appearing as cubic, octahedral, or dodecahedral forms, or in combinations.}$ $3.\ \text{Siderite, also called chalybite, iron carbonate (FeCO}_3), \text{a widespread mineral that is an ore of iron.}$ $\text{The mineral commonly occurs in thin beds with shales, clay, or coal seams (as sedimentary deposits) and in hydrothermal metallic veins (as gangue, or waste rock).}$ $4.\ \text{The Calamine – ZnCO}_3 \text{is a ore of zinc and it is zinc carbonate not zinc sulphate.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}