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Current Question (ID: 18494)

Question:

$\text{Why is roasting important in the iron metallurgy process?}$

Options:

1. $\text{FeO gets oxidized to Fe}_2\text{O}_3 \text{ which does not combine with acidic SiO}_2$
2. $\text{SiO}_2 \text{ is an acidic oxide which can combine with metallic oxides i.e. FeO, and Fe}_2\text{O}_3$
3. $\text{FeO when roasted get oxidized to more basic Fe}_2\text{O}_3$
4. $\text{None of the above.}$

Solution:

$\text{HINT: FeO gets converted to Fe}_2\text{O}_3$ $\text{Explanation:}$ $\text{Roasting is a process of heating a sulfide ore to a high temperature in the presence of air.}$ $\text{In case of Fe, roasting is required because FeO gets oxidized to Fe}_2\text{O}_3 \text{ which does not combine with acidic SiO}_2$ $\text{Otherwise FeO can form slag (FeSiO}_3) \text{ with SiO}_2.$ $\text{FeO + SiO}_2 \rightarrow \text{FeSiO}_3$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}