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Current Question (ID: 18503)

Question:
$\text{The correct statement among the following is:}$ $\text{1. The rate of reaction cannot be understood from the Ellingham diagram.}$ $\text{2. During the formation of metal oxide } \Delta S' \text{ becomes negative and } \Delta G \text{ becomes positive resulting in a positive slope.}$ $\text{3. There is an abrupt change in the slope of the Ellingham line when a change in phase (s} \rightarrow \text{l) or (l} \rightarrow \text{g) takes place.}$ $\text{4. All of the above.}$
Options:
  • 1. $\text{The rate of reaction cannot be understood from the Ellingham diagram.}$
  • 2. $\text{During the formation of metal oxide } \Delta S' \text{ becomes negative and } \Delta G \text{ becomes positive resulting in a positive slope.}$
  • 3. $\text{There is an abrupt change in the slope of the Ellingham line when a change in phase (s} \rightarrow \text{l) or (l} \rightarrow \text{g) takes place.}$
  • 4. $\text{All of the above.}$
Solution:
$\text{HINT: Application of Ellingham diagram}$ $\text{Explanation:}$ $\text{1. An Ellingham diagram is a graph showing the temperature dependence of the stability of compounds. This analysis is usually used to evaluate the ease of reduction of metal oxides and sulfides.}$ $\text{Thus, rate of reaction can not be understood by it.}$ $\text{2. } 2\text{M(s)} + \text{O}_2\text{(g)} \rightarrow 2\text{MO(s)}$ $\text{The number of gaseous molecules decreasing, hence entropy will decrease but } \Delta G \text{ will increase. In some cases, there is an abrupt change in the line's slope at a point because of a phase change.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}