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Current Question (ID: 18509)

Question:
$\text{Zinc cannot be extracted from zinc oxide via CO reduction because:}$ $\text{(Given: Ellingham diagram)}$
Options:
  • 1. $\Delta G_f^\circ \text{ of Zn from ZnO is lower than that of CO}_2 \text{ from CO}$
  • 2. $\Delta G_f^\circ \text{ of ZnO from Zn is lower than that of CO}_2 \text{ from CO}$
  • 3. $\text{ZnO is less stable than CO}$
  • 4. $\text{ZnO is more stable than CO}$
Solution:
$\text{HINT: } \Delta G_f^\circ \text{ of ZnO from Zn is lower than that of CO}_2 \text{ from CO}$ $\text{Explanation:}$ $\text{See Ellingham Diagram:}$ $\text{The standard Gibbs free energy of formation of ZnO from Zn is lower than that of CO}_2 \text{ from CO. Therefore, CO cannot reduce ZnO to Zn.}$ $\text{Hence, Zn is not extracted from ZnO through reduction using CO.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}