Import Question JSON

Current Question (ID: 18512)

Question:

$\text{Match the items in Column I with the items in Column II and assign the correct code.}$ $\text{Column I}$ $\text{A. Coloured Bands}$ $\text{B. Impure metal to volatile complex}$ $\text{C. Purification of Ge and Si}$ $\text{D. Purification of mercury}$ $\text{Column II}$ $1. \text{Zone refining}$ $2. \text{Fractional distillation}$ $3. \text{Mond's process}$ $4. \text{Chromatography}$ $5. \text{Liquation}$ $\text{Codes}$ $\begin{array}{cccc} \text{A} & \text{B} & \text{C} & \text{D} \\ 1. & 1 & 2 & 3 & 4 \\ 2. & 4 & 3 & 1 & 2 \\ 3. & 3 & 4 & 2 & 1 \\ 4. & 5 & 4 & 3 & 2 \end{array}$

Options:

1. $1 \ (3\%)$
2. $2 \ (93\%)$
3. $3 \ (4\%)$
4. $4 \ (3\%)$

Solution:

$\text{Hint: Purification of mercury is done by fractional distillation.}$ $\text{A. Coloured bands are observed in chromatography.}$ $\text{B. Impure metal is converted to a volatile complex by using Mond's process.}$ $\text{C. Purification of Ge and Si is purified by the zone refining method.}$ $\text{This method is very useful for producing semiconductors and other metals of very high purity, e.g., germanium, silicon, boron, gallium and indium.}$ $\text{D. Purification of mercury is done by fractional distillation.}$ $\text{This is very useful for low boiling metals like zinc and mercury.}$ $\text{The impure metal is evaporated to obtain the pure metal as distillate.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}