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Current Question (ID: 18513)

Question:

$\text{The method of purification that is represented by the following equation is:}$ $\text{Ti}(s) + 2\text{I}_2(g) \xrightarrow{523\ K} \text{TiI}_4(g)$ $\text{TiI}_4(g) \xrightarrow{1700\ K} \text{Ti}(s) + 2\text{I}_2(g)$

Options:

1. $\text{Cupellation}$
2. $\text{Poling}$
3. $\text{Van Arkel}$
4. $\text{Zone refining}$

Solution:

$\text{HINT: Follow, Van Arkel Method.}$ $\text{Explanation:}$ $\text{STEP 1:}$ $\text{Ultra purification methods of precious metals (Van Arkel Method):}$ $\text{This method is very useful for removing all the oxygen and nitrogen present}$ $\text{in the form of impurity in certain metals like Zr and Ti.}$ $\text{The crude metal is heated in an evacuated vessel with iodine. The metal}$ $\text{iodide being more covalent, and volatilize.}$ $\text{The reactions involved in the purification of Zr are as follows:}$ $\text{Zr} + 2\text{I}_2 \rightarrow \text{ZrI}_4$ $\text{STEP 2:}$ $\text{The metal iodide is decomposed on a tungsten filament, electrically heated}$ $\text{to about 1800K. The pure metal deposits on the filament.}$ $\text{ZrI}_4 \rightarrow \text{Zr} + 2\text{I}_2$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}