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Current Question (ID: 18514)

Question:
$\text{Which of the following statement is correct?}$ $\begin{array}{l} \text{1. Cast iron is obtained by remelting pig iron with scrap iron and coke using hot air blast.} \\ \text{2. In the extraction of silver, silver is extracted as a cationic complex.} \\ \text{3. Nickel is purified by zone refining.} \\ \text{4. Zr, and Ti are purified by the van Arkel method.} \end{array}$
Options:
  • 1. $(a, b)$
  • 2. $(b, c)$
  • 3. $(c, d)$
  • 4. $(a, d)$
Solution:
$\text{HINT: Nickel is purified by vapour phase refining method.}$ $\text{Explanation:}$ $(a) \text{ Cast iron is obtained by remelting pig iron with scrap iron and coke using hot air blast.}$ $(d) \text{ Zr and Ti are purified by van Arkel method as:}$ $\text{Zr}_{\text{Impure}} + 2\text{I}_2 \rightarrow \text{ZrI}_4 \xrightarrow{\Delta} \text{Zr}_{\text{Pure}} + 2\text{I}_2$ $(b) \text{ and } (c) \text{ can be correctly stated as:}$ $(b) \text{ In extraction of silver, silver is extracted as anionic complex } [\text{Ag} (\text{CN})_2]^{-}. $ $(c) \text{ In the vapour phase refining, the metal to be refined is converted into its volatile form which is collected and decomposed to give pure metal.}$ $\text{Nickel is purified by vapour phase refining method.}$ $\text{Ni} + 4\text{CO} \rightarrow \text{Ni} (\text{CO})_4 \rightarrow 450 - 470\text{K} \text{ Ni} + 4\text{CO}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}