Import Question JSON

Current Question (ID: 18518)

Question:

$\text{In the process of extraction of silver,}$ $\text{silver ore} + \text{CN}^- + \text{H}_2\text{O} + \text{O}_2 \rightarrow [\text{X}] + \text{OH}^-$ $[\text{X}] + \text{Zn} \rightarrow [\text{Y}] + \text{Ag}$ $[\text{X}], \text{and} [\text{Y}] \text{ in the above mentioned reaction are:}$

Options:

1. $\text{X} = [\text{Ag(CN)}_2]^- ; \text{Y} = [\text{Zn(CN)}_4]^{2-}$
2. $\text{X} = [\text{Ag(CN)}_2]^{3-} ; \text{Y} = [\text{Zn(CN)}_4]^{2-}$
3. $\text{X} = [\text{Ag(CN)}_2]^- ; \text{Y} = [\text{Zn(CN)}_6]^{4-}$
4. $\text{X} = [\text{Ag(CN)}_4]^- ; \text{Y} = [\text{Zn(CN)}_4]^{2-}$

Solution:

$\text{HINT: } \text{X}=[\text{Au(CN)}_2]^- \text{ and } \text{Y}=[\text{Zn(CN)}_4]^{2-}$ $\text{Explanation:}$ $\text{Leaching Process:}$ $\text{In the metallurgy of silver and gold, the respective metal is leached with a}$ $\text{dilute solution of NaCN or KCN}$ $\text{in the presence of air, which supplies } \text{O}_2. \text{ The metal is obtained later by}$ $\text{replacement reaction.}$ $\text{The reaction is as follows:}$ $4\text{Au} + 8\text{CN}^- + 2\text{H}_2\text{O} + \text{O}_2 \rightarrow 4[\text{Au(CN)}_2]^- + 4\text{OH}^-$ $2[\text{Au(CN)}_2]^- + \text{Zn} \rightarrow 2\text{Au} + [\text{Zn(CN)}_4]^{2-}$ $\text{It is Mac-Arthur process.}$ $\text{Here } \text{X}=[\text{Au(CN)}_2]^- \text{ and } \text{Y}=[\text{Zn(CN)}_4]^{2-}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}