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Current Question (ID: 18520)

Question:
$\text{The correct statement among the following is:}$ $1. \text{Blister copper has a blistered appearance due to the evolution of } \text{CO}_2.$ $2. \text{Vapour phase refining is carried out for nickel by the Van Arkel method.}$ $3. \text{Pig iron can be moulded into a variety of shapes.}$ $4. \text{Wrought iron is impure iron with 4 \% carbon.}$
Options:
  • 1. $\text{Blister copper has a blistered appearance due to the evolution of } \text{CO}_2.$
  • 2. $\text{Vapour phase refining is carried out for nickel by the Van Arkel method.}$
  • 3. $\text{Pig iron can be moulded into a variety of shapes.}$
  • 4. $\text{Wrought iron is impure iron with 4 \% carbon.}$
Solution:
$\text{HINT: Pig iron contains impurities (C, S, Si, P, etc) having malleable nature that's why can be molded.}$ $\text{Explanation:}$ $1. \text{Ultra purification methods for some precious metals and characteristic properties of Wrought iron and pig iron}$ $2. \text{Blister copper is due to the evolution of } \text{SO}_2$ $2 \text{Cu}_2 \text{O} + \text{Cu}_2 \text{S} \rightarrow 6\text{Cu} + \text{SO}_2$ $\text{The solidified copper obtained and so it is called blister copper.}$ $3. \text{The iron obtained from the Blast furnace contains about 4\% carbon and many impurities in smaller amounts}$ $(\text{e.g., S, P, Si, Mn}). \text{This is known as pig iron.}$ $\text{While wrought iron is a pure form of iron.}$ $4. \text{Nickel is purified by Mond's process}$ $\text{The Van Arkel method is a metallurgical method used to refine zirconium and titanium metal.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}