Import Question JSON

Current Question (ID: 18533)

Question:

$\text{The correct match among the following is:}$ $\begin{array}{|c|c|} \hline \text{Column I} & \text{Column II} \\ \hline \text{(a) Boron} & \text{(i) Van Arkel method} \\ \text{(b) Tin} & \text{(ii) Mond's process} \\ \text{(c) Zirconium} & \text{(iii) Liquation} \\ \text{(d) Nickel} & \text{(iv) Zone refining} \\ \hline \end{array}$

Options:

1. $\begin{array}{cccc} (a) & (b) & (c) & (d) \\ (i) & (iii) & (iv) & (ii) \end{array}$
2. $\begin{array}{cccc} (a) & (b) & (c) & (d) \\ (ii) & (iii) & (i) & (iv) \end{array}$
3. $\begin{array}{cccc} (a) & (b) & (c) & (d) \\ (iii) & (ii) & (i) & (iv) \end{array}$
4. $\begin{array}{cccc} (a) & (b) & (c) & (d) \\ (iv) & (iii) & (ii) & (i) \end{array}$

Solution:

$\text{1. Zone refining: In this method, a heater is fixed at one end of a rod of impure metal. As the heater moves,}$ $\text{the molten zone of the rod also moves along with it.}$ $\text{Due to this, pure metal crystallizes out and the impurities pass to the adjacent molten zone.}$ $\text{This process is repeated several times, which leads to the segregation of impurities at one end of the rod.}$ $\text{Then, the end with the impurities is cut off. Silicon, boron, gallium, indium etc. can be purified by this process.}$ $\text{2. Liquation Process: Liquation is a metallurgical technique to separate metals from an ore, metal or alloy.}$ $\text{This is done by heating the material until one of the constituents starts melting and the other remains solid.}$ $\text{The liquid melt is drained away from the other and collected.}$ $\text{Liquation is used for the refining of metals which are readily fusible, such as Pb, Sn, Bi and Hg as compared to impurities.}$ $\text{3. Mond process: In this process, nickel is heated in a stream of carbon monoxide forming a}$ $\text{volatile complex named nickel tetracarbonyl. This complex is decomposed at a}$ $\text{higher temperature to obtain pure metal.}$ $\text{The reaction is as follows:}$ $\text{Ni + 4CO} \rightarrow \text{Ni} \left( \text{CO} \right)_4$ $\text{Ni} \left( \text{CO} \right)_4 \rightarrow \text{Ni} + 4 \text{CO}$ $\text{4. Van Arkel process: This method is very useful for removing all the oxygen and nitrogen}$ $\text{present in the form of impurity in certain metals like Zr and Ti. The crude metal is heated in an}$ $\text{evacuated vessel with iodine.}$ $\text{The metal iodide being more covalent and volatilize.}$ $\text{Zr + 2I}_2 \rightarrow \text{ZrI}_4$ $\text{The metal iodide is decomposed on a tungsten filament, electrically heated to about 1800K.}$ $\text{The pure metal deposits on the filament.}$ $\text{ZrI}_4 \rightarrow \text{Zr} + 2\text{I}_2$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}