Import Question JSON

Current Question (ID: 18534)

Question:

$\text{What happens in the extraction of chlorine by electrolysis of brine?}$ $1.\ \text{Oxidation of } \text{Cl}^- \text{ ion to chlorine gas occurs.}$ $2.\ \text{Reduction of } \text{Cl}^- \text{ ion to chlorine gas occurs.}$ $3.\ \text{For overall reaction } \Delta G^\circ \text{ has negative value.}$ $4.\ \text{A displacement reaction takes place.}$

Options:

1. $\text{Oxidation of } \text{Cl}^- \text{ ion to chlorine gas occurs.}$
2. $\text{Reduction of } \text{Cl}^- \text{ ion to chlorine gas occurs.}$
3. $\text{For overall reaction } \Delta G^\circ \text{ has negative value.}$
4. $\text{A displacement reaction takes place.}$

Solution:

$\text{HINT: Oxidation of } \text{Cl}^- \text{ ion to chlorine gas occurs.}$ $\text{Explanation:}$ $\text{Following reaction takes place in the extraction of chlorine by electrolysis:}$ $2\text{H}_2\text{O} (l) + 2\text{Cl}^- (aq) \rightarrow \text{H}_2 (g) + \text{Cl}_2 (g) + 2\text{OH}^- (aq)$ $\text{From the above reaction it is very clear that the oxidation of } \text{Cl}^- \text{ to chlorine gas occurs. Thus, option (1) is the correct answer.}$ $\Delta G^\circ \text{ for this reaction is } +422 \text{kJ. Therefore, thermodynamically reaction is not feasible.}$ $\text{We know that,}$ $\Delta G^\circ = -nFE^\circ$ $\text{By using this equation value of } E^\circ \text{ can be calculated. Thus,}$ $E^\circ = -\frac{\Delta G^\circ}{nF} = -2.2 \text{V}$ $\text{Therefore, for the occurrence of this reaction, external potential (emf) greater than 2.2V is required. Due to this fact (3) is not the correct option.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}