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Current Question (ID: 18539)

Question:
$\text{Iron is extracted from chalcopyrite as:}$
Options:
  • 1. $\text{FeO}$
  • 2. $\text{FeS}$
  • 3. $\text{Fe}_2\text{O}_3$
  • 4. $\text{FeSiO}_3$
Solution:
$\text{Chalcopyrite is a copper iron sulfide mineral and the most abundant copper ore mineral.}$ $\text{It has the chemical formula CuFeS}_2 \text{ and crystallizes in the tetragonal system.}$ $\text{The concentrated ore is heated strongly with silicon dioxide (silica) and air or oxygen in a furnace or series of furnaces.}$ $\text{The copper(II) ions in the chalcopyrite are reduced to copper(I) sulfide (which is reduced further to copper metal in the final stage).}$ $2 \text{CuFeS}_2 + 5 \text{O}_2 + 2 \text{SiO}_2 \rightarrow 2 \text{Cu} + 4 \text{SO}_2 + 2 \text{FeSiO}_3 \text{(Slag)}$ $\text{Thus, FeO formed by roasting is removed as slag (FeSiO}_3\text{)}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}