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Current Question (ID: 18541)

Question:

$\text{In the metallurgy of aluminium:}$

Options:

1. $\text{Al}^{3+} \text{ is oxidised to Al(s).}$
2. $\text{The graphite anode is oxidised to carbon monoxide and carbon dioxide.}$
3. $\text{Oxidation state of oxygen change in the reaction at the anode.}$
4. $\text{The oxidation state of oxygen changes in the overall reaction involved in the process.}$

Solution:

$\text{HINT: Graphite anode is oxidised to carbon monoxide and carbon dioxide.}$ $\text{Explanation:}$ $\text{STEP 1:}$ $\text{In the metallurgy of aluminium, electrolysis is performed in a steel vessel}$ $\text{with the lining of carbon acting as cathode and graphite act as an anode.}$ $\text{During this process, graphite anode is oxidised to CO and CO}_2.$ $\text{The chemical reaction occurring in this process is as follows:}$ $2 \text{Al}_2\text{O}_3 + 3\text{C} \rightarrow 4\text{Al} + 3\text{CO}_2$ $\text{STEP 2:}$ $\text{This process is known as the Hall-Heroult process.}$ $\text{The electrolytic reactions are:}$ $\text{At cathode:}$ $\text{Al}^{3+}(\text{melt}) + 3\text{e}^- \rightarrow \text{Al}(\text{l})$ $\text{At anode:}$ $\text{C}(\text{s}) + \text{O}^{2-}(\text{melt}) \rightarrow \text{CO}(\text{g}) + 2\text{e}^-$ $\text{C}(\text{s}) + 2\text{O}^{2-}(\text{melt}) \rightarrow \text{CO}_2(\text{g}) + 4\text{e}^-$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}