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Current Question (ID: 18674)

Question:
$\text{The complex } [\text{Pt (NH}_3)_2\text{Cl(NH}_2\text{CH}_3)]\text{Cl correct IUPAC name is:}$
Options:
  • 1. $\text{Diamminechlorido(methylamine)platinum(II)chloride}$
  • 2. $\text{Diamminechloro(aminomethyl)platinum(II)chlorido}$
  • 3. $\text{Chlorodiammine(methylamine)platinate(II)chloride}$
  • 4. $\text{Chlorido(methylamine)diammineplatinum(II)chloride}$
Solution:
$\text{HINT: CH}_3\text{NH}_2 \text{ and NH}_3 \text{ are neutral ligands.}$ $\text{Explanation:}$ $\text{STEP 1:}$ $\text{In the given complex } [\text{Pt(NH}_3)_2\text{Cl(NH}_2\text{CH}_3)]\text{Cl, CH}_3\text{NH}_2 \text{ and NH}_3 \text{ are the neutral ligands.}$ $\text{The oxidation number of Pt is } +2. \text{ For NH}_3, \text{ diammine is used, and for Cl chlorido.}$ $\text{For CH}_3\text{NH}_2 \text{ methylamine is used.}$ $\text{STEP 2:}$ $\text{Let, the oxidation number of Pt is } \text{''}x\text{''}$ $x + (-1) = +1$ $x = +2$ $\text{STEP 3: The IUPAC name of the complex is Diamminechlorido(methylamine)platinum(II)chloride.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}