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Current Question (ID: 18675)

Question:

$\text{The hypothetical complex chlorodiaquatetraamminecobalt(III) chloride can be represented as:}$

Options:

1. $[\text{CoCl} (\text{NH}_3)_3 (\text{H}_2\text{O})_2] \text{Cl}_2$
2. $[\text{Co} (\text{NH}_3)_3 (\text{H}_2\text{O})\text{Cl}]_3$
3. $[\text{Co} (\text{NH}_3)_2 (\text{H}_2\text{O})_2 \text{Cl}]$
4. $[\text{Co} (\text{NH}_3)_3 (\text{H}_2\text{O})_3 \text{Cl}]_3$

Solution:

$\text{HINT: Aqua represents } \text{H}_2\text{O} \text{ ligand.}$ $\text{Explanation:}$ $\text{The given complex is chlorodiaquatetraamminecobalt (III) chloride.}$ $1. \text{``Aqua'' is used for } \text{H}_2\text{O} \text{ and ``di'' prefix is used. ``Amine'' is used for } \text{NH}_3 \text{ ligand, so ``tri'' represents three ligands.}$ $\text{``Chloro'' represents one Cl ligand is present inside the complex.}$ $2. \text{Chloride ligand is also present outside. Number of ligand can be calculated as:}$ $-1 + 3 = x \text{ (Charge on complex)}$ $\text{So, two Cl ligands are present outside the complex.}$ $3. \text{So, the complex will be: } [\text{CoCl} (\text{NH}_3)_3 (\text{H}_2\text{O})_2] \text{Cl}_2$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}