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Current Question (ID: 18676)

Question:
The IUPAC name of $[\text{Cr(en)}_3]\text{Cl}_3$ is:
Options:
  • 1. $\text{Triethylenediaminechromium (III) chloride}$
  • 2. $\text{Tris(ethylenediamine)chromium (II) chloride}$
  • 3. $\text{Tris(ethylenediamine)chromium (III) chloride}$
  • 4. $\text{Tris(ethylenediamine)chromium (II) chloride}$
Solution:
$\text{Oxidation state of Cr is +3}$ $\text{In the given compound } [\text{Cr(en)}_3]\text{Cl}_3 \text{, three ethylenediamine ligands are present so 'tris' will be used.}$ $\text{3Cl}^{-} \text{ ions are outside the sphere so, the complex will have +3 charge.}$ $\text{Let the oxidation state of Cr be } 'x'$ $x + 3(0) = +3$ $x = +3$ $\text{So, the oxidation state of chromium is +3.}$ $\text{Thus, the correct IUPAC name of the compound is tris(ethylenediamine)chromium (III) chloride.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}