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Current Question (ID: 18681)

Question:
$\text{The sum of the coordination number and oxidation number of the metal M in the complex } [\text{M(en)}_2(\text{C}_2\text{O}_4)]\text{Cl is:}$
Options:
  • 1. $9$
  • 2. $6$
  • 3. $7$
  • 4. $8$
Solution:
$\text{HINT: en and oxalate are bidentate ligands.}$ $\text{STEP 1: en is a neutral ligand and oxalate has -2 charge.}$ $\text{In } [\text{M(en)}_2(\text{C}_2\text{O}_4)]\text{Cl}$ $\text{Let oxidation number (OS) of M is } x.$ $\text{OS of oxalate ligand is } -2$ $\therefore x + (-2) = +1$ $x = +3$ $\text{STEP 2: The coordination number is the total number of binding sites attached to the metal.}$ $\text{Hence, the coordination number is 6 (en is bidentate and oxalate is also bidentate).}$ $\text{Thus, the sum of oxidation state and coordination sphere is 9.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}