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Current Question (ID: 18695)

Question:
$\text{Among the following, the compound that has the maximum coordination number is/are:}$ $1. [\text{Co(NH}_3\text{)}_6]^{3+}$ $2. [\text{Cr(C}_2\text{O}_4\text{)}_3]^{3-}$ $3. [\text{CoCl}_3(\text{H}_2\text{O})_3]$ $4. \text{All of the above have the same coordination number}$
Options:
  • 1. $[\text{Co(NH}_3\text{)}_6]^{3+}$
  • 2. $[\text{Cr(C}_2\text{O}_4\text{)}_3]^{3-}$
  • 3. $[\text{CoCl}_3(\text{H}_2\text{O})_3]$
  • 4. $\text{All of the above have the same coordination number}$
Solution:
$\text{HINT: Oxalato is a bidentate ligand.}$ $\text{Explanation:}$ $\text{STEP 1: The coordination number (C.N) of a metal ion in a complex can be defined as the number of ligand donor atoms to which the metal is directly bonded.}$ $\text{All complexes having 6 coordination numbers because in all complexes central atom is attached to 6 donor atoms.}$ $\text{STEP 2: The structures of complexes are:}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}