Import Question JSON

Current Question (ID: 18704)

Question:

$\text{If an excess of } \text{AgNO}_3 \text{ solution is added to } 100 \text{ mL of a } 0.024 \text{ M solution of dichlorobis (ethylenediamine) cobalt (III) chloride, then the number of moles of AgCl that will be precipitated is:}$

Options:

1. $0.0012$
2. $0.0016$
3. $0.0024$
4. $0.0048$

Solution:

$\text{HINT: One mole of Cl}^- \text{ gives one mole of AgCl}$ $\text{Explanation:}$ $\text{The formula of dichlorobis (ethylenediamine) cobalt (III) chloride is}$ $[\text{CoCl}_2 (\text{en})_2]\text{Cl which is having one ionisable Cl}^- \text{ ligand.}$ $[\text{CoCl}_2 (\text{en})_2]\text{Cl, the one-mole complex contains one mole of ionisable Cl}^-.$ $\therefore \text{ One mole of AgCl = One mole of complex = } \frac{100}{1000} \times 0.024 = 0.0024$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}