Import Question JSON

Current Question (ID: 18705)

Question:

$\text{When 0.1 mol of CoCl}_3(\text{NH}_3)_5 \text{ is treated with an excess of AgNO}_3, 0.2 \text{ mol of AgCl is obtained. The conductivity of the solution will correspond to:}$

Options:

1. $1:3 \text{ electrolyte}$
2. $1:2 \text{ electrolyte}$
3. $1:1 \text{ electrolyte}$
4. $3:1 \text{ electrolyte}$

Solution:

$\text{HINT: One mole of AgNO}_3 \text{ precipitates one mole of chloride ion.}$ $\text{Explanation:}$ $\text{In the above reaction, when 0.1 mole CoCl}_3(\text{NH}_3)_5 \text{ is treated with excess of AgNO}_3 \text{, 0.2 mole of AgCl are obtained thus, there must be two free chloride ions in the solution of electrolyte.}$ $\text{So, molecular formula of complex will be } [\text{Co (NH}_3)_5 \text{Cl}] \cdot \text{Cl}_2 \text{ and electrolytic solution must contain } [\text{Co (NH}_3)_5 \text{Cl}]^{2+} \text{ and 2 Cl}^- \text{ as consitituent ions.}$ $\text{Thus, it is 1:2 electrolyte.}$ $[\text{CoCl (NH}_3)_5] \cdot \text{Cl}_2 \rightarrow [\text{Co (NH}_3)_5 \text{Cl}]^{2+} \text{ (aq)} + 2 \text{Cl}^- \text{ (aq)}$ $\text{Hence, option (2) is the correct.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}