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Current Question (ID: 18716)

Question:
$\text{The compound that gives a pair of enantiomorphs is:}$ $\text{(en = NH}_2 \text{CH}_2\text{CH}_2\text{NH}_2\text{)}$
Options:
  • 1. $[\text{Co} (\text{NH}_3)_4\text{Cl}_2] \text{NO}_2$
  • 2. $[\text{Cr} (\text{NH}_3)_6][\text{Co} (\text{CN})_6]$
  • 3. $[\text{Co} (\text{en})_2\text{Cl}_2]\text{Cl}$
  • 4. $[\text{Pt} (\text{NH}_3)_4][\text{PtCl}_6]$
Solution:
$\text{HINT: } [\text{Co} (\text{en})_2\text{Cl}_2]\text{Cl} \text{ will give a pair of enantiomorphs.}$ $\text{Explanation:}$ $\text{Enantiomorphs or enantiomers are a pair of compounds which are non}$ $\text{superimposable mirror images of each other.}$ $\text{The example is } [\text{Co} (\text{en})_2\text{Cl}_2]^+ \text{ Dichlorobis [ethylene diamine] cobalt (III) can}$ $\text{occur as enantiomorphs as shown below.}$ $\text{All other are optically inactive. So, there will be no enantiomers for those}$ $\text{complexes.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}