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Current Question (ID: 18717)

Question:

$[\text{Co(NH}_3)_4(\text{NO}_2)_2]\text{Cl}$ \text{ can show:}

Options:

1. \text{Linkage isomerism, ionization isomerism and optical isomerism.}
2. \text{Linkage isomerism, ionization isomerism and geometrical isomerism.}
3. \text{Ionisation isomerism, geometrical isomerism and optical isomerism.}
4. \text{Ionisation isomerism, geometrical isomerism and optical isomerism.}

Solution:

$\text{HINT: It exhibits linkage, ionisation and geometrical isomerism.}$ $\text{Explanation:}$ $(i) \text{Linkage isomerism is the existence of coordination compounds that have the same composition differing with the connectivity of the metal to a ligand.}$ $\text{It's linkage isomers are: } [\text{Co(NH}_3)_4(\text{NO}_2)_2]\text{Cl and } [\text{Co(NH}_3)_4(\text{ONO})_2]\text{Cl}$ $(ii) \text{Ionisation isomerism is seen to occur in a complex salt when its counter ion is a potential ligand and this counter ion can displace a ligand making it to behave or become a counter ion.}$ $\text{It's ionisation isomers are } [\text{Co(NH}_3)_4(\text{NO}_2)\text{Cl}]\text{NO}_2 \text{ and } [\text{Co(NH}_3)_4(\text{NO}_2)_2]\text{Cl}$ $(iii) \text{Geometrical isomers are two or more coordination compounds which contain the same number and types of atoms, and bonds (i.e., the connectivity between atoms is the same), but which have different spatial arrangements of the atoms.}$ $\text{It's geometrical isomers are:}$ \text{(image of cis and trans isomers)} $\text{Thus, the complex } [\text{Co(NH}_3)_4(\text{NO}_2)_2]\text{Cl exhibits linkage, ionisation and geometrical isomerism.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}