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Current Question (ID: 18722)

Question:

$\text{The complex that does not exhibit optical isomerism is:}$ $\text{(en-ethylenediamine)}$

Options:

1. $[\text{Co(en)}_2\text{Cl}_2]^+$
2. $[\text{Co(NH}_3)_3\text{Cl}_3]$
3. $[\text{Co(en)Cl}_2(\text{NH}_3)_2]^+$
4. $[\text{Co(en)}_3]^{3+}$

Solution:

$\text{HINT: } [\text{Co(NH}_3)_3\text{Cl}_3] \text{ doesn't show optical isomerism.}$ $\text{Explanation:}$ $\text{STEP 1: If complex have elements of symmetry then it is optically inactive.}$ $\text{Optical isomerism is exhibited by only those complexes in which elements of symmetry are absent.}$ $\text{STEP 2: Octahedral complexes of the types [M(aa)}_3], [\text{M(aa)X}_2\text{Y}_2], \text{ and } [\text{M(aa)}_2\text{X}_2] \text{ have the absence of elements of symmetry, thus exhibit optical isomerism.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}