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Current Question (ID: 18743)

Question:
$\text{The geometry and magnetic properties of } [\text{NiCl}_4]^{2-}, \text{ respectively, are:}$
Options:
  • 1. $\text{Tetrahedral, Paramagnetic}$
  • 2. $\text{Tetrahedral, Diamagnetic}$
  • 3. $\text{Square planar, Paramagnetic}$
  • 4. $\text{Square planar, Diamagnetic}$
Solution:
$\text{HINT: Cl}^- \text{ is a weak field ligand.}$ $\text{Explanation: In } [\text{NiCl}_4]^{2-}, \text{ Cl}^- \text{ is a weak field ligand. So, pairing of electrons will not take place.}$ $\text{STEP 1:}$ $\text{The structure of } [\text{NiCl}_4]^{2-} \text{ is as follows:}$ $\text{The hybridization is } sp^3 \text{ and geometry is tetrahedral.}$ $\text{Complex contains two unpaired electrons, thus, it is paramagnetic in nature.}$ $\text{STEP 2:}$ $\text{The geometry of } [\text{NiCl}_4]^{2-} \text{ is:}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}