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Current Question (ID: 18746)

Question:

$\text{Among the following compounds, the paramagnetic compound with two unpaired electrons is:}$ $1. \text{K}_3[\text{Fe(CN)}_6]$ $2. \text{K}_2[\text{NiCl}_4]$ $3. \text{K}_2[\text{CoCl}_4]$ $4. \text{Na}_2[\text{Ni(CN)}_4]$

Options:

1. $\text{K}_3[\text{Fe(CN)}_6]$
2. $\text{K}_2[\text{NiCl}_4]$
3. $\text{K}_2[\text{CoCl}_4]$
4. $\text{Na}_2[\text{Ni(CN)}_4]$

Solution:

$\text{Hint: If molecule contains unpaired electron thus, it is paramagnetic in nature.}$ $\text{Consider the following table given below:}$ $\begin{array}{|c|c|c|c|} \hline \text{Complex} & \text{Metal oxidation state} & \text{Type of ligand} & \text{Electronic configuration of central metal atom} \\ \hline \text{K}_3[\text{Fe(CN)}_6] & +3 & \text{CN = Strong field ligand} & t_{2g}^5 e_g^0 \\ \text{K}_2[\text{NiCl}_4] & +2 & \text{Cl = Weak field ligand} & t_{2g}^6 e_g^2 \\ \text{K}_2[\text{CoCl}_4] & +2 & \text{Cl = Weak field ligand} & e_g^4 t_{2g}^3 \\ \text{Na}_2[\text{Ni(CN)}_4] & +2 & \text{CN = Weak field ligand} & 3d^8 \\ \hline \end{array}$ $\text{In } \text{K}_2[\text{NiCl}_4], \text{Ni}^{2+} \text{ contains 2 unpaired electrons. Hence, option two is the correct answer.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}