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Current Question (ID: 18752)

Question:
$\text{The complex that contains only one unpaired electron is:}$
Options:
  • 1. $[\text{CoF}_6]^{3-}$
  • 2. $[\text{Co(C}_2\text{O}_4)_3]^{3-}$
  • 3. $[\text{Fe(CN)}_6]^{3-}$
  • 4. $[\text{MnCl}_6]^{3-}$
Solution:
$\text{HINT: } [\text{Fe(CN)}_6]^{3-} \text{ contains only one unpaired electron.}$ $\text{Explanation: CN}^- \text{ and oxalate are strong field ligands (Metal is in +3 oxidation state). So, pairing will happen.}$ $\begin{array}{|c|c|c|c|} \hline \text{Complex} & \text{Metal ion} & \text{Electronic configuration} & \text{Unpaired electron/s} \\ \hline [\text{CoF}_6]^{3-} & \text{Co}^{+3} & t_{2g}^4 e_g^2 & 4 \\ \hline [\text{Co(C}_2\text{O}_4)_3]^{3-} & \text{Co}^{+3} & t_{2g}^6 e_g^0 & 0 \\ \hline [\text{Fe(CN)}_6]^{3-} & \text{Fe}^{+3} & t_{2g}^5 e_g^0 & 1 \\ \hline [\text{MnCl}_6]^{3-} & \text{Mn}^{+3} & t_{2g}^4 e_g^1 & 4 \\ \hline \end{array}$ $\text{So, } [\text{Fe(CN)}_6]^{3-} \text{ contains only one unpaired electron.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}