Import Question JSON

Current Question (ID: 18775)

Question:

$\text{The correct increasing order for the wavelengths of absorption in complexes of Co}^{3+} \text{ is:}$

Options:

1. $[\text{Co(H}_2\text{O)}_6]^{3+} < [\text{Co(en)}_3]^{3+} < [\text{Co(NH}_3)_6]^{3+}$
2. $[\text{Co(H}_2\text{O)}_6]^{3+} < [\text{Co(NH}_3)_6]^{3+} < [\text{Co(en)}_3]^{3+}$
3. $[\text{Co(NH}_3)_6]^{3+} < [\text{Co(en)}_3]^{3+} < [\text{Co(H}_2\text{O)}_6]^{3+}$
4. $[\text{Co(en)}_3]^{3+} < [\text{Co(NH}_3)_6]^{3+} < [\text{Co(H}_2\text{O)}_6]^{3+}$

Solution:

$\Delta_o \propto \text{Stronger ligand}$ $\Delta_o \text{ depends on the ligand if the central atom ion is same in complexes}$ $\Delta_o \propto \text{Stronger ligand}$ $\text{As energy is inversely proportional to the wavelength. Hence, } \Delta_o \text{ represents energy, } \Delta_o \text{ increases energy increases, and the wavelength decreases.}$ $\text{STEP 2: The increasing order of ligands according to their strength is as follows:}$ $\text{en} > \text{NH}_3 > \text{H}_2\text{O}$ $\text{The order of complexes, according to } \Delta_o \text{ is as follows:}$ $[\text{Co(H}_2\text{O)}_6]^{3+} < [\text{Co(NH}_3)_6]^{3+} < [\text{Co(en)}_3]^{3+}$ $\text{STEP 3: The increasing order for the wavelengths of absorption in the visible region for the complexes is as follows:}$ $[\text{Co(en)}_3]^{3+} < [\text{Co(NH}_3)_6]^{3+} < [\text{Co(H}_2\text{O)}_6]^{3+}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}