Import Question JSON

$\text{HINT: Greater the number of unpaired electrons, the larger is the paramagnetic character.}$ $\text{Explanation:}$ $\text{1. In } [\text{V(gly)}_2(\text{OH})_2(\text{NH}_3)_2]^+; \ V_{23} = [\text{Ar}] 4s^2 3d^3$ $\text{Oxidation state of V in } [\text{V(gly)}_2(\text{OH})_2(\text{NH}_3)_2]^+ \text{ is:}$ $X + (-1) \times 2 + (-1) \times 2 + (0) \times 2 = +1$ $x = +5$ $\text{Hence, } \text{V}^{5+} = [\text{Ar}] 3d^0 \ i.e. \ \text{No unpaired electron.}$ $\text{2. In } [\text{Fe(en)(bpy)(NH}_3)_2]^{2+}; \ \text{Fe}_{26} = [\text{Ar}] 4s^2 3d^6$ $\text{Oxidation state of Fe in } [\text{Fe(en)(bpy)(NH}_3)_2]^{2+} \text{ is:}$ $x + (0) + (0) + (0) \times 2 = +2$ $x = +2$ $\text{Hence, } \text{Fe}^{2+} = [\text{Ar}] 3d^6 \ i.e. \ \text{zero unpaired electron (en and bpy are strong field ligands)}$ $\text{3. In } [\text{Co(ox)}_2(\text{OH})_2]^-; \ \text{Co}_{27} = [\text{Ar}] 4s^2 3d^7$ $\text{Oxidation state of Co in } [\text{Co(ox)}_2(\text{OH})_2]^- \text{ is } x + (-2) \times 2 + (-1) \times 2 = -1$ $x - 6 = -1$ $x = +5 \ (4 \ \text{unpaired electrons})$ $\text{4. In } [\text{Ti(NH}_3)_6]^{3+}; \ \text{Ti}_{22} = [\text{Ar}] 4s^2, 3d^2$ $\text{The oxidation state of Ti in } [\text{Ti(NH}_3)_6]^{3+} \text{ is +3, thus it contains 1 unpaired electron.}$ $\text{Hence, } \text{Ti}^{+3} = [\text{Ar}] 4s^0 3d^1$ $\text{Hence, } [\text{Co(ox)}_2(\text{OH})_2]^- \text{ has the highest paramagnetic character due to the highest number of (4) unpaired electrons.}$