Import Question JSON

Current Question (ID: 18777)

Question:

$\text{Which among the following is incorrect?}$ $\begin{array}{|c|c|} \hline \text{Complex compounds} & \text{Type of hybridization} \\ \hline [\text{V(NH}_3)_6]^{3+} & d^2sp^3 \\ \hline [\text{CrCl}_3(\text{NMe}_3)_3] & d^2sp^3 \\ \hline [\text{Cu(CN)(NO}_2)(\text{NH}_3)(\text{py})] & dsp^2 \\ \hline \text{K}_3[\text{Co(ox)}_3] & sp^3d^2 \\ \hline \end{array}$

Options:

1. $[\text{V(NH}_3)_6]^{3+} \quad d^2sp^3$
2. $[\text{CrCl}_3(\text{NMe}_3)_3] \quad d^2sp^3$
3. $[\text{Cu(CN)(NO}_2)(\text{NH}_3)(\text{py})] \quad dsp^2$
4. $\text{K}_3[\text{Co(ox)}_3] \quad sp^3d^2$

Solution:

$\text{HINT: oxalate ligand is a strong ligand.}$ $\text{STEP 1: ox (oxalate) behave as strong field ligand. So, pairing of electrons will take place.}$ $\begin{array}{|c|c|c|c|} \hline \text{Complex} & \text{Electronic configuration (M}^{n+}\text{)} & \text{Hybridisation} & \text{Type of complex} \\ \hline \left[ \text{V(NH}_3)_6 \right]^{3+} & \text{V}^{3+} (d^2) & d^2sp^3 & \text{Inner orbital} \\ \hline \left[ \text{CrCl}_3(\text{NMe}_3)_3 \right] & \text{Cr}^{3+} (d^3) & d^2sp^3 & \text{Inner orbital} \\ \hline \left[ \text{Cu(CN)(NO}_2)(\text{NH}_3)(\text{py}) \right] & \text{Cu}^{2+} (d^9) & dsp^2 & \text{Inner orbital} \\ \hline \text{K}_3[\text{Co(ox)}_3] & \text{Co}^{3+} (d^6) & d^2sp^3 & \text{Inner orbital} \\ \hline \end{array}$ $\text{STEP 2: } \text{K}_3[\text{Co(ox)}_3] \text{ is inner orbital complex with } d^2sp^3 \text{ hybridisation.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}