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Current Question (ID: 18778)

Question:
$\text{The complex that does not have a tetrahedral shape is:}$
Options:
  • 1. $[\text{Cu} (\text{NH}_3)_4]^{2+}$
  • 2. $[\text{Ni} (\text{CO})_4]$
  • 3. $[\text{NiCl}_4]^{2-}$
  • 4. $[\text{Zn} (\text{NH}_3)_4]^{2+}$
Solution:
$\text{1. } [\text{Ni} (\text{CO})_4] \text{ hybridization is } sp^3. \text{ Ni is in a zero oxidation state. Thus its shape is tetrahedral.}$ $\text{2. } [\text{NiCl}_4]^{2-} \text{ hybridization is } sp^3. \text{ Ni is in a } +2 \text{ oxidation state here. Thus its shape is tetrahedral.}$ $\text{3. } [\text{Zn} (\text{NH}_3)_4]^{2+} \text{ hybridization is } sp^3. \text{ Here, Zn is in a } +2 \text{ oxidation state. Thus its shape is tetrahedral.}$ $\text{4. Only } [\text{Cu} (\text{NH}_3)_4]^{2+} \text{ is not tetrahedral because its hybridization is } dsp^2 \text{ and it is square planar.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}