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Current Question (ID: 18779)

Question:

$\text{Which of the following complex ions is Bronsted-Lowry acid?}$

Options:

1. $[\text{Cu} (\text{NH}_3)_4]^{2+}$
2. $[\text{FeCl}_4]^{-}$
3. $[\text{Fe} (\text{H}_2\text{O})_6]^{3+}$
4. $[\text{Zn} (\text{OH})_4]^{2-}$

Solution:

$\text{HINT: } [\text{Fe} (\text{H}_2\text{O})_6]^{3+} \text{ is Bronsted-Lowry acid.}$ $\text{Explanation:}$ $\text{STEP 1: A Bronsted-Lowry acid is a substance which donates a proton or } \text{H}^+ \text{ ion to the other compound and forms a conjugated base.}$ $\text{STEP 2: Octahedral aqua complexes of } \text{Fe}^{3+} \text{ and } \text{Al}^{3+} \text{ are Bronsted - Lowry}$ $\text{acid. It is because of more polarisation power of } \text{Fe}^{3+} \text{ due to high charge}$ $\text{density.}$ $\text{It will make -O-H bond weak and the release of } \text{H}^+ \text{ is feasible in that case.}$ $\text{The chemical reaction can be represented as:}$ $[\text{Fe} (\text{H}_2\text{O})_6]^{3+} \rightleftharpoons [\text{Fe} (\text{H}_2\text{O})_5 (\text{OH})]^{2+} + \text{H}^+$ $\text{Same is true for } \text{Al}^{3+} \text{ aqua complexes.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}