Import Question JSON

Current Question (ID: 18780)

Question:

$[\text{CoCl}_2(\text{NH}_3)_4]^+ + \text{Cl}^- \rightarrow [\text{CoCl}_3(\text{NH}_3)_3] + \text{NH}_3$ $\text{If in the above reaction, only one isomer of the product is obtained, then which of the following statement is true for the initial (reactant) complex?}$

Options:

1. $\text{Compound is in cis form.}$
2. $\text{Compound is in trans form.}$
3. $\text{Compound is in both (cis and trans) forms.}$
4. $\text{Can't be predicted.}$

Solution:

$\text{HINT: Cis isomer will give two products.}$ $\text{Explanation:}$ $\text{From Cis form, when one NH}_3 \text{ is replaced by one Cl then facial as well as meridional can be formed but from Trans form only meridional is formed by the replacement of NH}_3 \text{ from Cl.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}