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Current Question (ID: 18788)

Question:
$\text{An element among the following that exhibits the maximum oxidation state is:}$ $1. \ \text{Cr}$ $2. \ \text{Mn}$ $3. \ \text{Fe}$ $4. \ \text{V}$
Options:
  • 1. $\text{Cr}$
  • 2. $\text{Mn}$
  • 3. $\text{Fe}$
  • 4. $\text{V}$
Solution:
$\text{HINT: It depends on the electrons present in d- orbitals.}$ $\text{Explanation:}$ $\text{STEP 1:}$ $\begin{array}{ccc} \text{Element} & \text{Outer Electronic Configuration} & \text{Oxidation States} \\ \text{Fe} & 3d^6 4s^2 & +2, +3, +4, +5, +6 \\ \text{V} & 3d^3 4s^2 & +2, +3, +4, +5 \\ \text{Cr} & 3d^5 4s^1 & +2, +3, +4,+5, +6 \\ \text{Mn} & 3d^5 4s^2 & +2, +3, +4, +5, +6, +7 \end{array}$ $\text{STEP 2:}$ $\text{Manganese (Z = 25) exhibits largest number of oxidation states. This is}$ $\text{because its electronic configuration is } 3d^5 4s^2 \text{ and it has maximum number}$ $\text{of electrons (five d electrons and two s electrons) to lose or share.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}