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Current Question (ID: 18789)

Question:

$\text{Match the properties given in Column I with uses given in Column II}$ $\begin{array}{|c|c|} \hline \text{Column I-(Property)} & \text{Column II-(Metal)} \\ \hline \text{A. An element that can show +8 oxidation state} & \text{1. Mn} \\ \text{B. 3d block element that can show up to +7} & \text{2. Cr} \\ \text{C. 3d block element with the highest melting point} & \text{3. Os} \\ & \text{4. Fe} \\ \hline \end{array}$

Options:

1. $\begin{array}{ccc} \text{A} & \text{B} & \text{C} \\ 1 & 1 & 2 \\ \end{array}$
2. $\begin{array}{ccc} \text{A} & \text{B} & \text{C} \\ 2 & 1 & 2 \\ \end{array}$
3. $\begin{array}{ccc} \text{A} & \text{B} & \text{C} \\ 1 & 4 & 3 \\ \end{array}$
4. $\begin{array}{ccc} \text{A} & \text{B} & \text{C} \\ 4 & 2 & 3 \\ \end{array}$

Solution:

$\text{A. Osmium is an element that can show a +8 oxidation state because its electronic configuration is 5d}^6 \text{ 6s}^2 \text{ and all these electrons take part in the reaction.}$ $\text{B. 3d block element that can show up to +7 oxidation state is manganese because its electronic configuration is 3d}^5 \text{ 4s}^2 \text{ and all these electrons take part in the reaction.}$ $\text{C. 3d block element with the highest melting point is chromium.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}