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Current Question (ID: 18792)

Question:

$\text{Match Column I (Catalyst) with Column II (Process), and mark the appropriate option:}$ $\begin{array}{|c|c|} \hline \text{Column I - (Catalyst)} & \text{Column II - (Process)} \\ \hline \text{A. Ni in the presence of hydrogen} & \text{1. Contact process} \\ \text{B. Cu}_2\text{Cl}_2 & \text{2. Vegetable oil to ghee} \\ \text{C. V}_2\text{O}_5 & \text{3. Sandmeyer reaction} \\ \text{D. Finely divided iron} & \text{4. Haber's process} \\ & \text{5. Decomposition of KClO}_3 \\ \hline \end{array}$

Options:

1. $1, 3, 4, 2, 5$
2. $2, 3, 1, 4$
3. $5, 4, 3, 2$
4. $4, 5, 3, 2$

Solution:

$\text{The catalyst with their process is as follows:}$ $\text{A. Ni in the presence of hydrogen} \rightarrow \text{Vegetable oil to ghee}$ $\text{B. Cu}_2\text{Cl}_2 \rightarrow \text{Sandmeyer reaction}$ $\text{C. V}_2\text{O}_5 \rightarrow \text{Contact process}$ $\text{D. Finely divided iron} \rightarrow \text{Haber's process}$ $\text{Reactions:}$ $\text{SO}_2 \xrightarrow{\text{V}_2\text{O}_5} \text{SO}_3$ $\text{N}_2 + 3\text{H}_2 \xrightarrow{\text{Fe}} 2\text{NH}_3$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}