Import Question JSON

Current Question (ID: 18796)

Question:
$\text{What is the correct electronic configuration of Ti (Z = 22 atoms)?}$
Options:
  • 1. $1s^2 2s^2 2p^6 3s^2 3p^6 3d^2$
  • 2. $1s^2 2s^2 2p^6 3s^2 3p^6 3d^2 4p^6$
  • 3. $1s^2 2s^2 2p^6 3s^2 3p^6 3d^4$
  • 4. $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^2$
Solution:
$\text{HINT: Ti is a d block element.}$ $\text{Explanation: The atomic number of Ti is 22.}$ $\text{The general electronic configuration of d- block element is: } (n-1)d^{1-10}ns^{1-2}$ $\text{The electronic configuration of Ti is as follows:}$ $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^2$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}