Import Question JSON

Current Question (ID: 18800)

Question:
$\text{The correct statement(s) about transition elements are:}$
Options:
  • 1. $+2, \text{ and } +3 \text{ oxidation states are more common for elements in the first transition series, while higher oxidation states are more common for the heavier elements.}$
  • 2. $\text{The heavier transition elements form low-spin complexes only.}$
  • 3. $\text{The atomic sizes of the elements of the first transition series are smaller than those of the heavier elements (elements of 2nd and 3rd transition series).}$
  • 4. $\text{All of the above.}$
Solution:
$\text{Heavier transition metals show different properties than first transition elements.}$ $\text{(i) } +2 \text{ and } +3 \text{ oxidation states are more common for elements in the first transition series, while higher oxidation states are more common for the heavier elements.}$ $\text{(ii) The elements of the first transition series form low-spin or high-spin complexes depending upon the strength of the ligand field.}$ $\text{However, the heavier transition elements form only low-spin complexes, irrespective of the strength of the ligand field.}$ $\text{(iii) The atomic sizes of the elements of the first transition series are smaller than those of the heavier elements (elements of the 2nd and 3rd transition series).}$ $\text{However, the atomic sizes of the elements in the third transition series are virtually the same as those of the corresponding members in the second transition series. This is due to lanthanoid contraction.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}