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Current Question (ID: 18813)

Question:

$\text{A set of ions among the following that have a } 3d^2 \text{ electronic configuration is:}$

Options:

1. $\text{Ti}^{+}, \text{V}^{4+}, \text{Cr}^{6+}, \text{Mn}^{7+}$
2. $\text{Ti}^{4+}, \text{V}^{3+}, \text{Cr}^{2+}, \text{Mn}^{3+}$
3. $\text{Ti}^{2+}, \text{V}^{3+}, \text{Cr}^{4+}, \text{Mn}^{5+}$
4. $\text{Ti}^{3+}, \text{V}^{2+}, \text{Cr}^{3+}, \text{Mn}^{4+}$

Solution:

$\text{1. The electronic configuration of Ti (Atomic number = 22) is: [Ar] 3d^2 4s^2}$ $\text{Thus, Ti}^{2+} \text{ has configuration [Ar] 3d}^2$ $\text{2. The electronic configuration of V (Atomic no. = 23) is: [Ar] 3d^3 4s^2}$ $\text{Thus, V}^{3+} \text{ has [Ar] 3d}^2 \text{ configuration.}$ $\text{3. The electronic configuration of Cr (Atomic no. = 24) is: [Ar] 3d^4 4s^2}$ $\text{So, Cr}^{4+} \text{ has [Ar] 3d}^2 \text{ configuration.}$ $\text{4. The electronic configuration of Mn (Atomic no. = 25) is: [Ar] 3d^5 4s^2}$ $\text{So, Mn}^{5+} \text{ has [Ar] 3d}^2 \text{ configuration.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}