Import Question JSON

Current Question (ID: 18818)

Question:

$\text{Match the following:}$ $\begin{array}{|c|c|} \hline \text{Ions} & \text{Number of unpaired electrons} \\ \hline \text{i. Mn}^{3+} & \text{a. 2} \\ \text{ii. Cr}^{3+} & \text{b. 4} \\ \text{iii. V}^{3+} & \text{c. 1} \\ \text{iv. Ti}^{3+} & \text{d. 3} \\ \hline \end{array}$

Options:

1. $\begin{array}{cccc} \text{i. c} & \text{ii. d} & \text{iii. b} & \text{iv. a} \end{array}$
2. $\begin{array}{cccc} \text{i. b} & \text{ii. d} & \text{iii. a} & \text{iv. c} \end{array}$
3. $\begin{array}{cccc} \text{i. d} & \text{ii. b} & \text{iii. a} & \text{iv. c} \end{array}$
4. $\begin{array}{cccc} \text{i. b} & \text{ii. c} & \text{iii. d} & \text{iv. a} \end{array}$

Solution:

$\text{HINT: Follow the electronic configuration of given ions}$ $\text{Explanation:}$ $\text{The electronic configuration of given ions are as follows:}$ $\text{Mn}^{3+} = 3d^4 \ (4 \ \text{unpaired electrons})$ $\text{Cr}^{3+} = 3d^3 \ (3 \ \text{unpaired electrons})$ $\text{V}^{3+} = 3d^2 \ (2 \ \text{unpaired electrons})$ $\text{Ti}^{3+} = 3d^1 \ (1 \ \text{unpaired electron})$ $\text{The unpaired electron is equal to the number of electrons in the d orbital.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}