Import Question JSON

Current Question (ID: 18820)

Question:

$\text{Among the following, the incorrect statement regarding interstitial compounds is:}$ $\text{1. They retain metallic conductivity.}$ $\text{2. They are chemically reactive.}$ $\text{3. They are much harder than the pure metal.}$ $\text{4. They have higher melting points than the pure metal.}$

Options:

1. $\text{They retain metallic conductivity.}$
2. $\text{They are chemically reactive.}$
3. $\text{They are much harder than the pure metal.}$
4. $\text{They have higher melting points than the pure metal.}$

Solution:

$\text{HINT: They are chemically inert.}$ $\text{Explanation:}$ $\text{STEP 1: Interstitial compounds are obtained when small atoms like H, B, C, N etc., fit into the lattice of other elements.}$ $\text{Interstitial compounds are the combination of metals with non-metals where non-metals are smaller in size than metal e.g. Fe}_3\text{C is an interstitial compound.}$ $\text{Alloys are homogeneous solutions of metal and non-metal or metal with metal.}$ $\text{STEP 2: Because these tiny atoms are present at their interstitial places, the compounds are non-stoichiometric, which means that their precise proportion cannot be determined in the form of a well-defined number.}$ $\text{It should also be chemically inert. As a result, the chemical properties of the transition parent metal are unaffected, and its conductivity and reactivity are preserved.}$ $\text{STEP 3: It does improve the physical qualities of the compound, such as density, hardness, malleability, and ductility, due to its occupancy in the voids.}$ $\text{In addition, the connection between the interstitial atoms and the transition metals raises the melting and boiling points of the transition metals as compared to the parent metal.}$ $\text{Option 1, 3, and 4 are correct while Option 2 is incorrect.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}