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Current Question (ID: 18822)

Question:

$\text{Iron does not get oxidised in:}$

Options:

1. $\text{Rusting of iron sheets}$
2. $\text{Decolourisation of blue CuSO}_4 \text{ solution by iron}$
3. $\text{Formation of Fe(CO)}_5 \text{ from Fe}$
4. $\text{Liberation of H}_2 \text{ from steam by iron at a high temperature}$

Solution:

$\text{Iron is not getting oxidised during the formation of Fe(CO)}_5 \text{ from Fe.}$ $\text{Explanation: The reaction for given conditions are:}$ $\text{(1) Rusting of iron:}$ $\text{Fe}^0 + \text{H}_2\text{O} + \text{O}_2 \text{ air} \rightarrow \text{Fe}_2\text{O}_3 \cdot \text{xH}_2\text{O}$ $\text{(2) When Fe reacts with CuSO}_4 \text{ then oxidation of Fe takes place and Fe}^{2+} \text{ ion is obtained as a product.}$ $\text{Fe}^0 + \text{CuSO}_4 \rightarrow \text{FeSO}_4 + \text{Cu}$ $\text{(3) Formation of Fe(CO)}_5 \text{ from Fe is not an example of oxidation reaction because in both cases Fe oxidation state is zero.}$ $\text{Fe}^0 + 5\text{CO} \rightarrow \text{Fe(CO)}_5$ $\text{(4) Liberation of H}_2 \text{ from steam by iron at a high temperature}$ $\text{Fe}^0 + \text{H}_2\text{O} \text{ steam} \rightarrow \text{Fe}_2\text{O}_3 + \text{H}_2$ $\text{Thus, Formation of Fe(CO)}_5 \text{ does not involve oxidation of iron because oxidation state of iron is same.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}