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Current Question (ID: 18831)

Question:
$\text{Which of the following elements can combine with chlorine to form more than one binary compound?}$
Options:
  • 1. $\text{Zn}$
  • 2. $\text{K}$
  • 3. $\text{Ca}$
  • 4. $\text{Fe}$
Solution:
$\text{HINT: Fe can form a binary compound.}$ $\text{Explanation:}$ $\text{STEP 1:}$ $\text{A binary compound is one made of two different elements. These can be one of each element such as CuCl}_2 \text{ or FeO. There can also be several of each element such as Fe}_2\text{O}_3\text{, or SnBr}_4\text{.}$ $\text{STEP 2:}$ $\text{Metals that have variable oxidation numbers can form more than one type of binary compound like Fe shows the oxidation state +2 and +3. Hence it forms two types of binary compounds. e.g., FeCl}_2\text{, FeCl}_3\text{.}$ $\text{STEP 3:}$ $\text{Zn and Ca shows only a +2 oxidation state and K shows only a +1 oxidation state.}$ $\text{Thus, only Fe can form binary compounds among these.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}