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Current Question (ID: 18862)

Question:
$\text{An incorrect statement regarding the stability of oxidation state for the elements of the 3d series is:}$
Options:
  • 1. $\text{The number of oxidation states increases on moving from Sc to Mn.}$
  • 2. $\text{The relative stability of the +2 oxidation state increases on moving from top to bottom.}$
  • 3. $\text{The relative stability of the +2 oxidation state decreases on moving from top to bottom.}$
  • 4. $\text{Both (1) and (2)}$
Solution:
$\text{HINT: Transition element shows variable oxidation state because of the presence of (n-1) d orbitals.}$ $\text{Explanation:}$ $\text{STEP 1: The maximum number of oxidation states is shown by Mn, varying from +2 to +7. The number of oxidation states increases on moving from Sc to Mn.}$ $\text{On moving from Mn to Zn, the number of oxidation states decreases due to a decrease in the number of available unpaired electrons.}$ $\text{STEP 2: The relative stability of the +2 oxidation state increases on moving from top to bottom.}$ $\text{This is because on moving from top to bottom, it becomes more and more difficult to remove the third electron from the d-orbital.}$

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Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}