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Current Question (ID: 18863)

Question:
$\text{Which of the following statements is false?}$
Options:
  • 1. $\text{MnO}_2 \text{ dissolves in conc. HCl, but does not form Mn}^{4+} \text{ ions.}$
  • 2. $\text{MnO}_2 \text{ oxidizes hot concentrated H}_2\text{SO}_4 \text{ liberating oxygen.}$
  • 3. $\text{K}_2 \text{MnO}_4 \text{ is formed when MnO}_2 \text{ infused KOH is oxidized by air, KNO}_3, \text{ PbO}_2 \text{ or NaBiO}_3$
  • 4. $\text{The decomposition of acidic KMnO}_4 \text{ is not catalyzed by sunlight.}$
Solution:
$\text{HINT: Decomposition of acidic KMnO}_4 \text{ is catalyzed by sunlight.}$ $\text{Explanation:}$ $1. \text{MnO}_2 \text{ dissolves in conc. HCl and forms Mn}^{2+} \text{ ions.}$ $\text{MnO}_2 + 4\text{HCl(Conc.)} \rightarrow \text{MnCl}_2 + \text{Cl}_2 + \text{H}_2\text{O}$ $2. \text{MnO}_2 \text{ oxidizes hot concentrated H}_2\text{SO}_4 \text{ liberating oxygen.}$ $2\text{MnO}_2 + 2\text{H}_2\text{SO}_4 \rightarrow 2\text{MnSO}_4 + 2\text{H}_2\text{O} + \text{O}_2$ $3. \text{K}_2 \text{MnO}_4 \text{ is formed when MnO}_2 \text{ infused KOH is oxidized by air, KNO}_3, \text{ PbO}_2 \text{ or NaBiO}_3$ $2\text{KOH} + \text{MnO}_2 + \text{O} \rightarrow \text{K}_2 \text{MnO}_4 + \text{H}_2\text{O}$ $4. \text{Under sunlight, permanganate solution will decompose to give MnO}_2 \text{ and O}_2.$ $2\text{KMnO}_4(\text{aq}) \rightarrow \text{K}_2 \text{MnO}_4(\text{aq}) + \text{MnO}_2(\text{aq}) + \text{O}_2(\text{g})$ $\text{Dark bottles are used to cut off sunlight and so, KMnO}_4 \text{ are stored in dark bottles.}$

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Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}