Import Question JSON

Current Question (ID: 18867)

Question:

$\text{Select the appropriate statement(s) from the following options:}$

Options:

1. $\text{The maximum oxidation state of the d block elements appears in the middle and the minimum at the extreme ends.}$
2. $\text{IE}_1 \text{ of third transition series elements is smaller than IE}_1 \text{ of second and first transition series elements.}$
3. $\text{The atomic sizes of the elements in the 3d series are greater than those in the 4d or 5d series.}$
4. $\text{Both (1) and (2)}$

Solution:

$\text{HINT: The element present in middle shows maximum oxidation states.}$ $\text{Explanation:}$ $\text{(i) In each of the three transition series the number of oxidation states shown by the elements is the maximum in the middle and the minimum at the extreme ends.}$ $\text{However, +2 and +3 oxidation states are quite stable for all elements present in the first transition series.}$ $\text{(ii) The first ionization enthalpies of the third transition series are higher than those of the first and second transition series. This occurs due to the poor shielding effect of 4f electrons in the third transition series.}$ $\text{(iii) Atomic size generally decreases from left to right across a period.}$ $\text{Now, among the three transition series, atomic sizes of the elements in the second transition series are greater than those of the elements corresponding to the same vertical column in the first transition series.}$ $\text{However, the atomic sizes of the elements in the third transition series are virtually the same as those of the corresponding members in the second transition series. This is due to lanthanoid contraction.}$

Import JSON File

Upload a JSON file containing LaTeX/MathJax formatted question, options, and solution.

Expected JSON Format:

{
  "question": "The mass of carbon present in 0.5 mole of $\\mathrm{K}_4[\\mathrm{Fe(CN)}_6]$ is:",
  "options": [
    {
      "id": 1,
      "text": "1.8 g"
    },
    {
      "id": 2,
      "text": "18 g"
    },
    {
      "id": 3,
      "text": "3.6 g"
    },
    {
      "id": 4,
      "text": "36 g"
    }
  ],
  "solution": "\\begin{align}\n&\\text{Hint: Mole concept}\\\\\n&1 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\text{ moles of carbon atom}\\\\\n&0.5 \\text{ mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6] = 6 \\times 0.5 \\text{ mol} = 3 \\text{ mol}\\\\\n&1 \\text{ mol of carbon} = 12 \\text{ g}\\\\\n&3 \\text{ mol carbon} = 12 \\times 3 = 36 \\text{ g}\\\\\n&\\text{Hence, 36 g mass of carbon present in 0.5 mole of } \\mathrm{K}_4[\\mathrm{Fe(CN)}_6].\n\\end{align}",
  "correct_answer": 4
}